Real-Life Math -- Solution
Do the math:
T = square root of (2 x D / G)
T = square root of (2 x 25 / 9.8)
T = square root of 5.10
T = 2.26 seconds to the ground
If your forward velocity is going to be 3 m/sec, then:
3 x 2.26 = 6.78 m out from the wingtip
The bag better be there when you arrive.
V = G x T
V = 9.8 x 2.26
V = 22.15 m/sec
You'll be going 22.15 meters per second when you land 6.78 meters out from the wingtip 2.26 seconds after you jump.
1 foot = 0.3 meters
6.78 meters / 0.3 meters per foot = 22.6 feet
That 6.78 meters is 22.6 feet out there -- just so everyone in the crew knows!
How much math does a stunt performer have to do in the real world?
"Zero," says David Boushey. He is the coordinator of the Stunt School of United Stuntmen's Association. He has 20 years of experience as a professional stunt performer, coordinator and stunt instructor.
Usually, the stunt performer has an intuitive sense of how to do a stunt, he says. If there are any calculations to make, they're usually done by a specialist, such as the stunt coordinator or the rigger.
For example, in a scene where a car jumps 36 meters, someone has to calculate the speed the car needs to be traveling, and at what angle the ramp needs to be.