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Industrial Instrumentation Technician

Real-Life Activities

Real-Life Math -- Solution

Part A:

The turbine generated 180 pulses per gallon of oil flow. You know there are 3.78 liters in 1 U.S. gallon. You need to find the number of pulses generated per liter of oil flow.

180 pulses per gallon / 3.78 liters per gallon = 47.6 pulses per liter

The turbine generates 47.6 pulses per liter of oil flow.

Part B:

The ammeter registered 4 mA of current for each pulse generated per second. You know from part A that 47.6 pulses are generated for each liter of oil flowing through the turbine. You have to find out how many mA are registered by the ammeter when 1 liter per second of oil is flowing.

4 mA of current per pulse per second x 47.6 pulses per second = 190.4 mA

The ammeter registers 190.4 mA when 1 liter per second of oil is flowing.

"Math is used pretty extensively in this profession," says Bob Goudy, an industrial instrumentation technician. "You need a solid grounding in math and physics."


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